Question

How do you write in slope intercept with only the rate of change and one point. Like rate of change is -5 and the point is (3,0)

Answer 1

A linear equation in the slope-intercept form is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

Now, we know that the rate of change (the slope) is -5

Then we just replace a by -5

y = -5*x + b

Now we also know that this line passes through a point, and the point is (3, 0)

This means that the point (3, 0) is a solution for the line equation, so when x = 3, we also have y = 0.

Replacing these values in our equation we get:

0 = -5*3 + b

0 = -15 + b

15 = b

Now we know the value of b, so we can replace it in the line equation to get:

y = -5*a + 15

Which is the complete equation of the line.