Question

Use the graph to answer the question.

On a coordinate plane, a line goes from (negative 5, 7) to (3, 3).

Which parametric equations describe the curve?


x = –t + 1 and y = 0.5t + 4 when –2 ≤ t ≤ 6

x = –t + 1 and y = 0.5t + 4 when –5 ≤ t ≤ 3

x = 0.5t + 4 and y = –t + 1 when –2 ≤ t ≤ 6

x = 0.5t + 4 and y = –t + 1 when –5 ≤ t ≤ 3

Answer 1

The answer for this question is A:

A = x = –t + 1 and y = 0.5t + 4 when –2 ≤ t ≤ 6