Question

If the logarithm of 5832 is 6, what is the base?

`logx(5832) = 6`
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Answer 1

The base is 4.2426.

Explanation:

Logarithm definition:

Suppose we have that:

`log_a(b) = c`

It means that;

`b = a^c`

In this question:

`log_x((5832)) = 6`

It means that:

`x^6 = 5832`

`x = \sqrt[6]{5832}`

`x = (5832)^{(1)/(6)}`

`x = 4.2626`

The base is 4.2426.