Question

9. The gradient of the curve y=kx⁴ at the point x = 2 is 128. Find the value of k.​

Answer 1

k = 4

Explanation:

Here, we want to find the value of k

Mathematically, the gradient of a curve is same as the first derivative

so the first derivative here is;

dy/dx = 4kx^3

Now, the value of x here is 2 while the value of y is 128

Substituting these values;

128 = 4k(2)^3

128 = 32k

k = 128/32

k = 4