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3. A ray of monochromatic light (1 = 5.9 x 10-7 meters) traveling in air is

incident on an interface with a liquid at an angle of 45° as shown in
the diagram to the right. If the absolute index of refraction of the
liquid is 1.4, calculate the angle of refraction.

3. A ray of monochromatic light (1 = 5.9 x 10-7 meters) traveling in air is incident-example-1

2 Answers

3 votes

Answer:

45 degrees༼ つ ◕_◕ ༽つ

Step-by-step explanation:

User Himanshu Dudhat
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The angle of refraction of the ray of monochromatic light is 30.3⁰.

How to calculate the angle of refraction?

The angle of refraction is calculated by applying Senil's law as follows;

n₁ sin (θ₁) = n₂ sin (θ₂)

Where;

  • n₁ is the refractive index of the first medium (air)
  • θ₁ is the angle of incidence,
  • n₂ is the refractive index of the second medium (the liquid),
  • θ₂ is the angle of refraction

The angle of refraction is calculated as;

n₁ sin (θ₁) = n₂ sin (θ₂)

1 x sin (45) = 1.4 sin (θ₂)

sin (θ₂) = sin (45) / 1.4

sin (θ₂) = 0.505

θ₂ = arc sin (0.505)

θ₂ = 30.3⁰

User SrAxi
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