Question

10 If Steve was making a solution of ammonium

chloride, how many grams would he have left

undissolved (if any) if he initially placed 140 g of

the chemical into 200 grams of water at 80 °C.

Answer 1

8.8g of ammonium chloride would be undissolved.

Step-by-step explanation:

The solubility of ammonium chloride at 80°C is: 65.6g / 100mL

As the solubility is 65.6g / 100mL, in 200g = 200mL the solubility will be:

65.6g * 2 =

131.2g / 200g

That means the water at this temperature will dissolve 131.2g of ammonium chloride. As were placed 140g, the mass that will be undissolved is:

140g - 131.2g =

8.8g of ammonium chloride would be undissolved