Question

How many grams of Si are there in a sample of Si that contains the same number of moles as a 60.8 gram sample of P?

Answer 1

55.1 g Si.

Step-by-step explanation:

Hello there!

In this case, for the given mole-mole relationship, it is possible to set up the following mole ratio as the moles of Si and P are the same:

1 mol Si = 1 mol P.

Next, since one mole of silicon has a mass of 28.09 g and one of phosphorous of 31.0 g, we can set up the following expression for the mass of silicon:

`60.8gP*(1molP)/(31.0gP)*(1molSi)/(1molP)*(28.09gSi)/(1molSi)`

Therefore, the result is 55.1 grams of silicon.

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