Answer: C) scalene
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Step-by-step explanation:
Use the distance formula to calculate the distance from R to S. This is identical to the length of segment RS.
![R = (x_1,y_1) = (-3,-1) \text{ and } S = (x_2, y_2) = (0,3)\\\\d = √((x_1 - x_2)^2 + (y_1 - y_2)^2)\\\\d = √((-3-0)^2 + (-1-3)^2)\\\\d = √((-3)^2 + (-4)^2)\\\\d = √(9 + 16)\\\\d = √(25)\\\\d = 5\\\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/qsx4ebp897jbqq6e97pxpuk4fn7mvdog3s.png)
Segment RS is exactly 5 units long.
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Repeat similar steps to find the length of segment ST
![S = (x_1,y_1) = (0,3) \text{ and } T = (x_2, y_2) = (3,0)\\\\d = √((x_1 - x_2)^2 + (y_1 - y_2)^2)\\\\d = √((0-3)^2 + (3-0)^2)\\\\d = √((-3)^2 + (3)^2)\\\\d = √(9 + 9)\\\\d = √(18)\\\\d \approx 4.2426\\\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/hu8aq88lfzd8mlho5j64d6pbkvqc08eyr1.png)
ST is roughly 4.2426 units long.
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Lastly, let's calculate the length of segment TR.
![T = (x_1,y_1) = (3,0) \text{ and } R = (x_2, y_2) = (-3,-1)\\\\d = √((x_1 - x_2)^2 + (y_1 - y_2)^2)\\\\d = √((3-(-3))^2 + (0-(-1))^2)\\\\d = √((3+3)^2 + (0+1)^2)\\\\d = √((6)^2 + (1)^2)\\\\d = √(36 + 1)\\\\d = √(37)\\\\d \approx 6.0828\\\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/a3f0qxe4gpa59f8qu22um4n3vhckudfubm.png)
TR is about 6.0828 units long.
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Summary of the segment lengths:
- RS = 5 exactly
- ST = 4.2426 approximately
- TR = 6.0828 approximately
The three sides are different lengths.
Therefore, the triangle is scalene.