Question

What volume of a 2.0M NaOH(aq) is needed to completely neutralize 24 milliliters of 0.5M HCl(aq)?

Show numerical setup and answer.

Answer 1

`V_(base)=6.0mL`

Step-by-step explanation:

Hello there!

In this case, by considering that the reaction between sodium hydroxide and hydrochloric acid is in a 1:1 mole ratio of these two reactants, we are able to use the following equation relating the concentration and volume of each one:

`M_(acid)V_(acid)=M_(base)V_(base)`

In such a way, by solving for the volume of the base, we will obtain:

`V_(base)=(M_(acid)V_(acid))/(M_(base)) \\\\V_(base)=(0.5M*24mL)/(2.0M)\\\\V_(base)=6.0mL`

Regards!