Question

Find the distance to the nearest tenth

between the points (-4, 2) and (6, -3) on
the coordinate plane.

Answer 1

d=11.2

Explanation:

`d=\sqrt{(x2-x1)^(2)+(y2-y1)^(2) \\ }`

`d=\sqrt{(6-(-4)^(2)+(-3-2)^(2) }`

`d=\sqrt{10^(2)+5^(2) }`

`d=√(100+25)`

`d=√(125)`

`d=11.18`

`d=11.2`