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Find the distance to the nearest tenth between the points (-4, 2) and (6, -3) on the coordinate plane.
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Find the distance to the nearest tenth

between the points (-4, 2) and (6, -3) on
the coordinate plane.

User Rover
by
6.1k points

1 Answer

4 votes

Answer:

d=11.2

Explanation:


d=\sqrt{(x2-x1)^(2)+(y2-y1)^(2) \\ }


d=\sqrt{(6-(-4)^(2)+(-3-2)^(2) }


d=\sqrt{10^(2)+5^(2) }


d=√(100+25)


d=√(125)


d=11.18


d=11.2

User Jonas Kohl
by
5.8k points
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