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If 5.25 mL of HCl requires 4.96 mL of 0.9845 M NaOH to reach the equivalence point,

what is the concentration of the HCI?

User Krevan
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M_(A)V_(A)=M_(B)V_(B)\\(5.25)M_(A)=(4.96)(0.9845)\\M_(A)=((4.96)(0.9845))/(5.25) \approx \boxed{0.93 \text{ M}}

If 5.25 mL of HCl requires 4.96 mL of 0.9845 M NaOH to reach the equivalence point-example-1
User Krishna Gupta
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