Question

2. A kayaker is paddling south at 2.50 m/s, and encounters a weird current moving 1.15 m/s west.

What is the resultant velocity?

Answer 1

v = 2.91 m/s

Step-by-step explanation:

Given that,

A kayaker is paddling south at 2.50 m/s, and encounters a weird current moving 1.15 m/s west.

We need to find the resultant velocity. Both velocities are perpendicular to each other. So,

`v=√(v_1^2+v_2^2) \\\\=√(2.5^2+1.5^2) \\\\=2.91\ m/s`

So, the magnitude of the resultant velocity is equal to 2.91 m/s.