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An object is dropped from a height of 1168 feet above the ground.

How high above the ground will the object be after 6 seconds?
Incorrect
feet
Correct

How long after being dropped will the object reach the ground? (if necessary, round to the nearest tenth)

1 Answer

3 votes

9514 1404 393

Answer:

592 feet

8.5 seconds

Explanation:

The usual equation used for ballistic motion is ...

h(t) = -16t^2 +h0

Here, we have h0=1168 and t=6, so ...

h(t) = -16(6^2) +1168 = 592 . . . feet high after 6 seconds

__

For h(t) = 0, the value of t can be found from ...

0 = -16t^2 +1168

t^2 = 1168/16 = 73

t = √73 ≈ 8.5

The object will reach the ground after 8.5 seconds.

User PMende
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