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A 25 N force stretches a spring 280 cm. What was the spring constant? ​

A 25 N force stretches a spring 280 cm. What was the spring constant? ​-example-1
User Malika
by
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2 Answers

7 votes

Answer:

  1. F= 25N
  2. ∆l=280cm
  3. K=?
  4. you apply the formula = K:F/∆l
  5. = 0,089N/cm
User Dveim
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3.7k points
8 votes

Hi there!

Using Hooke's Law:

F = kx

F = Force (N)

k = Spring constant (N/m)

x = displacement (m)

Begin by converting cm to m:

280 cm = 2.8 m

Now, plug in the givens:

25 = 2.8k

k = 8.93 N/m

User Matt Sweeney
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3.5k points