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A 905 kg test car travels around a 3.25 km circular track. if the magnitude of the force that maintains the car's circular motion is 2140 N, what is the car's tangential speed?
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A 905 kg test car travels around a 3.25 km circular track. if the magnitude of the force that maintains the car's circular motion is 2140 N, what is the car's tangential speed?

User Michoel
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Link provided in other answer is a SCAM, don’t click on the link !!!!
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User Henrik Hansen
asked Apr 4, 2021 228k views
2140=(905)(v^2)/3.25
Henrik Hansen asked Apr 4, 2021
by Henrik Hansen
8.2k points
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