Given:
Numbers on die = 1, 2, 3, 4
Colors on board = Red, Green, Blue, Orange (equal sized sections)
To find:
The number of different possible outcomes are there if she rolls a fair die in the board.
Solution:
According to the given information,
The total possibilities for numbers = 4
Total possibilities for colors = 4
Total possibilities = Possibilities for number × Possibilities for colors
=
=
So, total 16 possible outcomes are there if she rolls a fair die in the board.
Let Red=R, Green=G, Blue=B, Orange=O, then list of total possible outcomes is:
{1R,1G,1B,1O,2R,2G,2B,2O,3R,3G,3B,3O,4R,4G,4B,4O}
Therefore, the total possible outcomes are 16 and the lies of outcomes is {1R,1G,1B,1O,2R,2G,2B,2O,3R,3G,3B,3O,4R,4G,4B,4O}.