Question

a gas occupies 100.0 mL at a pressure of 780 mm Hg. What is the pressure of the gas when its volume is decreased to 25.0 mL?

Answer 1

`P_2=3120mmHg`

Step-by-step explanation:

Hello there!

In this case, according to the Gay-Lussac's law, which sets up the pressure-volume behavior as a directly proportional relationship:

`P_1V_1=P_2V_2`

Thus, since we are asked for the final pressure, P2, we obtain:

`P_2=(P_1V_1)/(V_2) =(780mmHg*100.0mL)/(25.0mL)\\\\P_2=3120mmHg`

Best regards!