Question

18. A 35.0 G piece of metal wire is heated and the temperature changes from 21°C to 52°C the specific heat of the metal is 0.900 J/G degrees Celsius how much energy was required to heat the metal please show work

Answer 1

Q = 976.5 J.

Step-by-step explanation:

Hello there!

In this case, according to the thermodynamic definition of the heat in terms mass, specific heat and temperature change, we can write:

`Q=mC(T_2-T_1)`

Thus, by plugging in the given data, we obtain:

`Q=35.0g*0.900(J)/(g\°C) (52\°C-21\°C)\\\\Q=976.5J`

Regards!