Question

An apple costs $2.00 more than amango. The total cost of

three apples and a mango is $50.00.
put it in algebra pls
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Answer 1

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Answer 2

1 mango = 11 dollars

1 apple = 13 dollars

Explanation:

Let
`a` be equal to the cost of an apple.

Let
`m` be equal to the cost of a mango.

1) Create equations

An apple costs $2.00 more than a mango.

⇒
`m+2=a` (the cost of a mango + 2 dollars = cost of an apple)

The total cost of three apples and a mango is $50.00.

⇒
`3a+m=50` (3 apples*the cost of 1 apple + cost of 1 mango = 50 dollars)

2) Solve for m and a

`3a+m=50`

Substitute a with
`m+2`

`3(m+2)+m=50\\3m+6+m=50\\4m+6=50`

Subtract both sides by 6

`4m+6-6=50-6\\4m=44`

Divide both sides by 4

`(4m)/(4)=(44)/(4) \\m=11`

Therefore, the cost of 1 mango is 11 dollars.

`m+2=a`

Substitute m with 11 to solve for a

`11+2=a\\13=a`

Therefore, the cost of 1 apple is 13 dollars.

I hope this helps!