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The sample mean tip amount for the 20 parties to which the waitress gave her name was $5.44, with a standard deviation of $1.75. These statistics were $3.49 and $1.13, respectively, for the 20 parties to which the waitress did not give her name. The data were not strongly skewed in either group.

Required:
Use appropriate symbols for the six numbers reported in this paragraph.

User Rich Jenks
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1 Answer

4 votes

Answer:

First sample size,
n_(x) = 20

Second sample size,
n_(y) = 20

Sample mean of first sample,
\bar{x} = 5.44

Sample mean of second sample,
\bar{y} = 3.49

Sample Standard deviation of first sample,
\sigma_(x) = 1.75

Sample Standard deviation of second sample,
\sigma_(y) = 1.13

Explanation:

Given - The sample mean tip amount for the 20 parties to which the waitress gave her name was $5.44, with a standard deviation of $1.75. These statistics were $3.49 and $1.13, respectively, for the 20 parties to which the waitress did not give her name. The data were not strongly skewed in either group.

To find - Use appropriate symbols for the six numbers reported in this paragraph.

Proof -

First sample size,
n_(x) = 20

Second sample size,
n_(y) = 20

Sample mean of first sample,
\bar{x} = 5.44

Sample mean of second sample,
\bar{y} = 3.49

Sample Standard deviation of first sample,
\sigma_(x) = 1.75

Sample Standard deviation of second sample,
\sigma_(y) = 1.13

User Whiskey
by
8.6k points

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