Question

The loudness (L) of sound in decibels is related to intensity (Umeasured watts per square centimeter by the equation L=10log( 1/(10 ^ - 16) Find the loudness of a whisperat 10^ -12 W/cm^ 2

Answer 1

40

Explanation:

Answer 2

The loudness of the sound is equal to 40 decibels.

Explanation:

Given that,

The loudness (L) of sound in decibels is related to intensity by the equation as follows :

`L=10\ log((I)/(I_0))`

Where

I is the intensity of sound

I₀ is the least audible sound

Put
`I=10^(-12)\ W/m^2 \ and\ I_0=10^(-16)\ W/m^2`

So,

`L=10\ log((10^(-12))/(10^(-16)))\\\\L=40\ dB`

So, the loudness of the sound is equal to 40 decibels.