The loudness (L) of sound in decibels is related to intensity (Umeasured watts per square centimeter by the equation L=10log( 1/(10 ^ - 16) Find the loudness of a whisperat 10^ …

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asked Oct 20, 2022 79.2k views

2 Answers

Jeff Hykin · Answer 1 · 2022-10-24T16:17:24+0000

Answer:

The loudness of the sound is equal to 40 decibels.

Explanation:

Given that,

The loudness (L) of sound in decibels is related to intensity by the equation as follows :

$L=10\ log((I)/(I_0))$

Where

I is the intensity of sound

I₀ is the least audible sound

Put
$I=10^(-12)\ W/m^2 \ and\ I_0=10^(-16)\ W/m^2$

So,

$L=10\ log((10^(-12))/(10^(-16)))\\\\L=40\ dB$

So, the loudness of the sound is equal to 40 decibels.