Question

14. A light bulb has a resistance of 8 ohms and a maximum current of 10 A How much voltage can

be applied before the bulb will break?

Answer 1

80 volts.

Step-by-step explanation:

From the question,

Applying Ohm's law

V = IR...................... Equation 1

Where V = Voltage, I = maximum current of the bulb, R = Resistance of the bulb.

Given: I = 10 A, R = ohms

Substitute these values into equation 1

V = 10×8

V = 80 volt.

Hence the voltage that can be applied is 80 volt.