On the grid, A(-3,1), B(1,-2), and C(4,2) are connected. Kaire claims triangle ABC is a right isosceles triangle.

Question

asked Nov 14, 2023 226k views

1 Answer

Aziza Kasenova · Answer 1 · 2023-11-20T16:13:40+0000

Answer:

part A:

$\sf AB^2 = (-2-1)^2 + (1+3)^2$

$\sf AB^2 =25$

$\sf AB =5$

$\sf AC^2 = (2-1)^2 + (4+3)^2$

$\sf AC^2 = 50$

$\sf AC = 5√(2)$

$\sf BC^2 = (2--2)^2 + (4-1)^2$

$\sf BC^2 = 25$

$\sf BC = 5$

Two sides are equal in the triangle of 5. Its an isosceles triangle.

part B:

if right angle triangle, then use the formula:

short side² + short side² = long side²

( 5√2 )² + 5² = ( 5√2 )²

75 = 50

Therefore, its not a right angle triangle.