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Solve triangles using the law of sines

Solve triangles using the law of sines-example-1
User BankZ
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1 Answer

6 votes

Answer:

BC = 18.7

Explanation:

Here, we want to solve the triangle using the law of sines

According to the law, the ratio of the measure of the side of a triangle and the sine of the angle that faces the side is a constant for all sides of the triangle

Mathematically;

a/sin A = b/sin B = c/sin C

with reference to this particular triangle, we have it that;

20/sin 80 = BC/ sin 67

BC = 20 * sin 67/sin 80

BC = 18.7

User Puttputt
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