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How many solutions can be found for the equation 3z + 2[z - 3) = 7z+12

User Maurycyt
by
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2 Answers

3 votes

Given :-

3z + 2(z - 3) = 7z + 12

Solution :-

3z + 2(z - 3) = 7z + 12

3z + 2z - 6 = 7z + 12

3z + 2z - 7z = 12 + 6

5z - 7z = 18

-2z = 18

z = 18/2

z = 9


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Answered by - ItzMaster

User Martin Janiczek
by
6.5k points
1 vote

Given :-

3z + 2(z - 3) = 7z + 12

Solution :-

3z + 2(z - 3) = 7z + 12

3z + 2z - 6 = 7z + 12

3z + 2z - 7z = 12 + 6

5z - 7z = 18

-2z = 18

z = 18/2

z = 9


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Answered by - ItzAdmire

User Roger Steinberg
by
7.4k points