Question

How many solutions can be found for the equation 3z + 2[z - 3) = 7z+12

Answer 1

Given :-

3z + 2(z - 3) = 7z + 12

Solution :-

3z + 2(z - 3) = 7z + 12

3z + 2z - 6 = 7z + 12

3z + 2z - 7z = 12 + 6

5z - 7z = 18

-2z = 18

z = 18/2

z = 9

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Answered by - ItzMaster

Answer 2

Given :-

3z + 2(z - 3) = 7z + 12

Solution :-

3z + 2(z - 3) = 7z + 12

3z + 2z - 6 = 7z + 12

3z + 2z - 7z = 12 + 6

5z - 7z = 18

-2z = 18

z = 18/2

z = 9

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Answered by - ItzAdmire