Question

Can somebody help? please.

Answer 1

`x=(\sqrt6 \sqrt 2)/(2)`

Explanation:

We need to find the value of x.

Here, Hypotenuse = √6

Perpendicular = x

We know that,

`\sin\theta=(P)/(H)`

So,

`\sin(45)=(x)/(\sqrt6)\\\\x=\sin(45)* √(6) \\\\x=(√(6))/(√(2) )\\\\x=(√(6))/(√(2) )* (\sqrt2)/(\sqrt2)\\\\x=(\sqrt6 * \sqrt 2)/(2)\\\\x=(\sqrt6 \sqrt 2)/(2)`

So, the value of x is equal to
`(\sqrt6 \sqrt 2)/(2)`.