Question

The difference between two numbers is 7. The sum of twice the larger number and three times the smaller number is 19.

Answer 1

x= 8 y= 1

Explanation:

First, you identify your variables:

x= larger number

y= smaller number

Second, you find your equations:

x - y = 7

2x + 3y = 19

Third, (I used the substitution method) you make "y" by itself for the 1st equation.

y = x - 7

2x + 3y = 19

Then, you plug in the 1st equation for "y" in the 2nd equation

2x + 3(x - 7) = 19

Then, you distribute and simplify.

2x + 3x - 21 = 19

5x - 21 = 19

5x = 40

x = 8

Finally, you plug in the variable you found ( x ) into one of the equations and solve,

8 - y = 7

- y = -1

y = 1