Answer:
Expression 2b+b and 3b have same values for all values of b.
Explanation:
Given the two expression 2b+b2b+b and 3b3b and values of b as 1, 2 and 3.
Consider first expression that is, 2b+b2b+b .
Substituting the value of b=1b=1 ,
2\left(1\right)+\left(1\right)=2+1=32(1)+(1)=2+1=3 ....1
Substituting the value of b=2b=2 ,
2\left(2\right)+\left(2\right)=4+2=62(2)+(2)=4+2=6 ....2
Substituting the value of b=3b=3 ,
2\left(3\right)+\left(3\right)=6+3=92(3)+(3)=6+3=9 ....3
Consider second expression that is, 3b3b .
Substituting the value of b=1b=1 ,
3\left(1\right)=33(1)=3 ....4
Substituting the value of b=2b=2 ,
3\left(2\right)=63(2)=6 ....5
Substituting the value of b=3b=3 ,
3\left(3\right)=93(3)=9 ....6
For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.
Therefore both expression are same for all values of b.
Explanation:
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