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How many liters of carbon monoxide are needed to react with 32.65 g oxygen gas to produce carbon dioxide?

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Answer:

2.040 mol CO

Step-by-step explanation:

First, write out your reaction:

CO + O2 --> CO2

Balance the reaction:

2CO + O2 --> 2CO2

Now divide the 32.65 g O2 by the molar mass of O2 (32.00 g/mol) to get moles of O2. Then multiply by the mole ratio of 2 mol CO for every 1 mol O2 to get moles of CO needed to fully react.

32.65 g O2 / 32.00 g/mol = 1.020 mol O2

1.020 mol O2 • 2 mol CO / 1 mol O2 = 2.040 mol CO

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