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A balloon is filled with oxygen gas with a volume of 8.70 ML and a temperature of 318.2 K if the temperature increases to 337.8 K what would the new volume be

User Dieter B
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1 Answer

2 votes

Answer:

The new volume will be 9.24 mL.

Step-by-step explanation:

Charles's law determines that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

So, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:


(V)/(T) =k

When studying an initial state 1 and a final state 2, it is satisfied:


(V1)/(T1) =(V2)/(T2)

In this case:

  • V1= 8.70 mL
  • T1= 318.2 K
  • V2= ?
  • T2= 337.8 K

Replacing:


(8.70 mL)/(318.2 K) =(V2)/(337.8 K)

Solving:


V2=337.8K*(8.70 mL)/(318.2 K)

V2= 9.24 mL

The new volume will be 9.24 mL.

User Shezad
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