Answer: A
Explanation: The sum of the multiplicities must be .
n
.
Starting from the left, the first zero occurs at =−3.
x
=
−3.
The graph touches the x-axis, so the multiplicity of the zero must be even. The zero of −3
−3
has multiplicity 2.
2.
The next zero occurs at =−1.
x
=
−1.
The graph looks almost linear at this point. This is a single zero of multiplicity 1.
The last zero occurs at =4.
x
=
4.
The graph crosses the x-axis, so the multiplicity of the zero must be odd. We know that the multiplicity is likely 3 and that the sum of the multiplicities is likely 6.