Question

Please help! Solve the following:

Answer 1

n=10.

Explanation:

`(45)/(n^(2)-3n-4 )` -
`(3)/(n-4)` =
`(2)/(n+1 )`

`(45)/(n^(2)-3n-4 )` -
`(3(n+1))/((n+1)(n-4))` =
`(2(n-4))/((n+1)(n-4) )`

`(45)/(n^(2)-3n-4 )` -
`(3n+3)/(n^(2) -3x-4)` =
`(2n-8)/(n^(2) -3x-4 )`

45-3n-3=2n-8

45-3+8=5n

n=50/5=10