Question

Please write the equation and help me solve. please no links

Answer 1

Answer: The molality of solution is 1.2 mole/kg

Step-by-step explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

`Molality=(n)/(W_s)`

where,

n = moles of solute

`W_s` = weight of solvent in kg

Given : 10 g of glycerol is present in 100 g of solution

moles of glycerol =
`\frac{\text {given mass}}{\text {molar mass}}=(10g)/(92g/mol)=0.108mol`

mass of water (solvent )= (100-10) = 90 g = 0.09 kg

Now put all the given values in the formula of molality, we get

`Molality=(0.108mol)/(0.09kg)=1.2mole/kg`

Therefore, the molality of solution is 1.2 mole/kg