Answer:
power input = -66.2798 kW
Step-by-step explanation:
Steady state pressure ( Cp ) = 1.05 bar,
Temperature ( T1 ) = 300 K
Volumetric flow rate = 30 m^3/min
exit pressure = 12 bar
exit temperature ( T2 ) = 400 K
Heat transfer rate ( Q ) = 5 kW
Calculate the power input in kW
p1v1 = m RT
m = p1v1 / RT1
= (1.05 * 10^2 * ( 30/60 )) / ( 0.287 * 300 )
= 0.60975 m^3/sec
also
h1 + Q = h2 + w
∴ w = m ( h1 - h2 ) + Q
= mCp ( t1 - t2 ) + Q ----- ( 1 )
where : ( Q ) = 5 kW , Cp = 1.05 bar, t1 = 300 K, t2 = 400 k ( input values into equation 1 )
w = -66.2798 kW