Final answer:
To determine solubility in water, refer to solubility rules. Ammonium acetate, Barium hydroxide, Sodium hydroxide, and Rubidium nitrate are soluble. Iron (II) carbonate is insoluble.
Step-by-step explanation:
To determine which compounds are soluble in water and which are insoluble, we can refer to the solubility rules of ionic compounds. The solubility rules state that compounds containing alkali metal cations (such as Na+ and K+) and ammonium ions (NH4+) are soluble in water. Compounds containing nitrate (NO3-), acetate (CH3COO-), and chlorate (ClO3-) ions are also soluble. On the other hand, compounds containing carbonate (CO3^2-), phosphate (PO4^3-), sulfide (S^2-), oxide (O^2-), and hydroxide (OH-) ions are insoluble in water, except for those containing alkali metal cations and NH4+.
- a. NH4CH3COO: Ammonium acetate is soluble in water.
- b. Ba(OH)2: Barium hydroxide is soluble in water.
- c. FeCO3: Iron (II) carbonate is insoluble in water.
- d. NaOH: Sodium hydroxide is soluble in water.
- e. RbNO3: Rubidium nitrate is soluble in water.