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A non-cold-worked 1040 steel cylindrical rod has an initial length of 100 mm and initial diameter of 7.50 mm. is to be deformed using a tensile load of 18,000 N. It must not experience either plastic deformation or a diameter reduction of more than 1.5 x 10-2 mm. Would the 1040 steel be a possible candidate for this application

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Answer:

1040 steel will be a possible candidate for this application since : Yield strength > stress

Step-by-step explanation:

The 1040 steel would be a possible candidate for this application because the stress experienced by the load is Lesser than its Yield strength

Given that 1040 steel has the following parameter values

Modulus of elasticity ( GPa ) = 205

Yield strength ( Mpa ) = 450

Poisson's ratio = 0.27

limitation of = 1.5 x 10^-2 mm.

stress = Tensile load / area of steel

= 18,000 N / 4.418 * 10^-5 m^2

= 407 .424 Mpa

User Sherwood Botsford
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