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A soccer ball is kicked from the ground with an initial upward velocity of 64 meters per second, and the height of the ball can be represented by the equation h = -16t^2 + 64t. After how many seconds will the ball hit the ground?

User El Zorko
by
5.3k points

1 Answer

7 votes

Answer:

t = 2 seconds

Explanation:

Given that,

h = -16
t^(2) + 64 t

where h and t have their usual meaning.

To determine the number of seconds required of the ball to hit the ground, differentiate the given equation with respect to t.

0 = -32 + 64

So that,

32t = 64

t =
(64)/(32)

t = 2

The ball will hit the ground in 2 seconds.

User Lingo
by
5.4k points
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