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The triangle on the grid will be translated two units left.

On a coordinate plane, triangle A B C has points (negative 1, negative 1), (negative 1, negative 5), (0.5, negative 5).

Which shows the triangle when it is translated two units left?
On a coordinate plane, triangle A prime B prime C prime has points (1, negative 1), (1, negative 5), (2.5, negative 5).
On a coordinate plane, triangle A prime B prime C prime has points (negative 3, negative 1), (negative 3, negative 5), (negative 1.5, negative 5).
On a coordinate plane, triangle A prime B prime C prime has points (negative 1, 1), (negative 1, negative 3), (0.5, negative 3).
On a coordinate plane, triangle A prime B prime C prime has points (negative 1, negative 3), (negative 1, negative 7), (0.5, negative 7)

2 Answers

7 votes

Answer:

B

Explanation:

User Chihung Yu
by
8.5k points
2 votes

Given:

The vertices of a triangle are A(-1,-1), B(-1,-5), C(0.5,-5).

The figure is translated 2 units left.

To find:

The vertices and the diagram of the triangle after the given translation.

Solution:

if a figure is translated 2 units left, then


(x,y)\to (x-2,y)

Using the above rule, we get


A(-1,-1)\to A'(-1-2,-1)


A(-1,-1)\to A'(-3,-1)

Similarly,


B(-1,-5)\to B'(-1-2,-5)


B(-1,-5)\to B'(-3,-5)

And,


C(0.5, -5)\to C'(0.5-2,-5)


C(0.5, -5)\to C'(-1.5,-5)

So, the vertices of the triangle after the translation are A'(-3,-1), B'(-3,-5), C'(-1.5,-5).

Therefore, the correct option is B.

User Misha Vyrko
by
8.0k points

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