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Solve the system 8y-5z=23 3y-2z=6

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User Cookesd
by
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1 Answer

4 votes

Answer:

z = 21 ; y= 16

Explanation:

first of all we have to isolate a variable.

In second expression we can obtain:

3y = 2z+6

y = 2/3 z + 2

now we have to substitute this value in the first equation and solve it

8(2/3z+2)-5z = 23

16/3z + 16 -5z = 23

16z +48 - 15z = 69

z = 21

now we have to substitute z in the second equation:

y = 2/3 (21) +2

y = 14+ 2 = 16

y = 16

User Victor Grazi
by
4.2k points