Question

A baseball is thrown with a speed of 36 meters per second (m/s). What is the distance from the mound to home plate if the ball takes 0.5 seconds to leave the pitcher's hand and cross the plate? A-72 B-18 C-41 D-31 Help me out please

Answer 1

d = 18 m

Step-by-step explanation:

Given that,

The speed of a baseball, v = 36 m/s

We need to find the distance from the mound to home plate if the ball takes 0.5 seconds to leave the pitcher's hand and cross the plate.

Let the distance be d. We can find it using the formula,

Speed = distance/time

or

`d=vt\\\\d=36* 0.5\\\\d=18\ m`

So, the required distance is equal to 18 m.