Question

3a-2/3+2a+3/2=a+7/6.find a ​

Answer 1

I think your question seems to be ;

`{\:\implies \quad \sf 3a-\frac23 +2a+\frac32 =a+\frac76}`

So I will be solving for that ;

`{\:\implies \quad \sf 3a+2a+\left(\frac32 -\frac23\right)=a+\frac76}`

`{\:\implies \quad \sf 5a+\left((9-4)/(6)\right)=a+\frac76}`

`{\:\implies \quad \sf 5a+\frac56 =a+\frac76}`

`{\:\implies \quad \sf 5a-a=\frac76 -\frac56}`

`{\:\implies \quad \sf 4a=(7-5)/(6)}`

`{\:\implies \quad \sf 4a=\frac26}`

`{\:\implies \quad \sf 4a=\frac13}`

`{\:\implies \quad \sf a=(1)/(3\cdot 4)}`

`{\:\implies \quad \bf \therefore \quad \underline{\underline{a=(1)/(12)}}}`