Answer:
1231.5 m³
Explanation:
You have to find the height first.
using the Pythagoras rule,
hypotaneous² = base² + height²
25² = 7² + h²
576 = h²
h = √576
h = 24
Volume of cone = 1/3 π r² h
= 1/3 * π* 7² * 24
= 1231.5 m³
1232m^3
d = 14m
r = 7m
l = 25m
h = ?
h = root l^2- r^2
h = root 25^2- 7^2
h = root 625- 49
h = root 576
h = 24m
volume of cone = 1/3 pie r^2 h
= 1/3*22/7* 7*7*24
= 22*7*8
= 154*8
= 1232m^3
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