Question

A 1-kg ball is 12 m above the ground, with an initial velocity = 0 m/s.

Use the following formulas
[ KE = 1/2 xm x V2]
[P.E = mxgxh] . g =9.8 m/s2
[ Mechanical energy = K.E + P.E]

Answer 1

M = 117.6 J

Step-by-step explanation:

Given that,

The mass of a ball, m = 1kg

The height of the ball, h = 12 m

At point A, its initial velocity, v = 0

The mechanical energy is the sum of kinetic and potential energy such that,

`M=(1)/(2)mv^2+mgh\\\\M=0+mgh\\\\M=1* 9.8* 12\\\\M=117.6\ J`

So, the mechanical energy is equal to 117.6 J.