Question

Imagine that you have an ideal gas in a 5.80 L container, and that 2950 molecules of this gas collide with a square-centimetre area of the container at any given instant.

If the volume is increased to 46.4 L at constant temperature, how many collisions will occur per square centimetre of this larger container?

Answer 1

23,600 collisions.

Step-by-step explanation:

Hello there!

In this case, according to the Avogadro's law, which help us to understand the molecules-volume relationship as directly proportional:

`(molecules_2)/(V_2)=(molecules_1)/(V_1)`

It is possible for us to compute the collisions once the volume is increased as shown below:

`molecules_2=(molecules_1V_2)/(V_1)\\\\molecules_2=(2950*46.4L)/(5.80L)\\\\molecules_2=23600`

Which means 23,600 collisions will occur per square centimeter.

Regards!