148k views
4 votes
The function h defined by h(t)=(-4.9t + 29.4)(t+2) models the height in meters, of an object t seconds after it is launched. When will the object hit the ground?

1 Answer

1 vote

Answer:

The time the object will hit the ground is 2 s.

Explanation:

Given;

h(t) = (-4.9t + 29.4)(t + 2)

Open the bracket;

h(t) = -4.9t² + 29.4t -9.8t + 58.8

h(t) = -4.9t² + 19.6t + 58.8

When the object hit the ground, the final velocity will be zero;


v = (dh)/(dt) = 0 \\\\(dh)/(dt) = -9.8t + 19.6 = 0\\\\9.8t = 19.6\\\\t = (19.6)/(9.8) \\\\t = 2 \ s

Therefore, the time the object will hit the ground is 2 s.

User David Goldfarb
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories