4 NH3 + 302 2N2 + 6H₂O 2.) a) A chemist burned 0.25 moles of ammonia gas (NH,) in the presence of excess oxygen pps to produce 2.95 grams of nitrogen gas (N2). Calculate the theoretical yield of nitrogen

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asked Dec 14, 2022 201k views

2 votes

4 NH3 + 302

2N2 + 6H₂O
2.) a) A chemist burned 0.25 moles of ammonia gas (NH,) in the presence of excess oxygen
pps to produce 2.95 grams of nitrogen gas (N2). Calculate the theoretical yield of
nitrogen gas.

Chemistry
high-school

Alexandresecanove asked

by Alexandresecanove

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2 Answers

5 votes

Answer:

I'm not sure but maybe 1 g ?!

4 NH3 + 302 2N2 + 6H₂O 2.) a) A chemist burned 0.25 moles of ammonia gas (NH,) in-example-1

Stafford answered Dec 15, 2022

by Stafford

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5 votes

Answer:

this is hard

Step-by-step explanation:

Louis Loo answered Dec 21, 2022

by Louis Loo

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