Question

I need the answer , help me pls

Answer 1

`\large \boxed{y = - (2)/(3) x + 2}`

Explanation:

both slopes multiply each others must equal to -1 for perpendicular.

`\large{m_1m_2 = - 1}`

Let m1 = 3/2

`\large{ (3)/(2) m_2 = - 1} \\ \large{3m_2 = - 2} \\ \large{m_2 = - (2)/(3) }`

Therefore -2/3 is perpendicular to 3/2. Because the line passes through (6,-2)

`\large{y - y_1 = m(x - x_1)}`

Given (x1, y1) = ordered pair

Therefore (x1, y1) = (6,-2)

and m = - 2/3

`\large{y + 2 = - (2)/(3) (x - 6)}`

Write in slope-intercept form.

`\large{y = - (2)/(3) x + 4 - 2} \\ \large{y = - (2)/(3)x + 2}`