Question

Please help me
and show me step by step​

Answer 1

6. mean = 1.4

7. variance = 1.64

standard deviation = √1.64

Explanation:

6.

`\textsf{mean }\mu=\[ \sum [x \cdot p(x)]`

⇒
`\mu` = 0 x 0.4 + 1 x 0.1 + 2 x 0.2 + 3 x 0.3 = 1.4

7. see attached for completed table

`\textsf{variance }\sigma^2=\[ \sum [(x -\mu)^2 \cdot p(x)]`

Therefore, variance is the total of the last column:

`\sigma^2` = 0.784 + 0.016 + 0.072 + 0.768 = 1.64

standard deviation is the square root of variance:

`\sigma=√(1.64)`